8x^2-64x+56=0

Solution for 8x^2-64x+56=0 equation:

8x^2-64x+56=0

a = 8; b = -64; c = +56;
Δ = b2-4ac
Δ = -642-4·8·56
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-48}{2*8}=\frac{16}{16}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+48}{2*8}=\frac{112}{16}
=7
$